t^2-9.25t-9.25=0

Solution for t^2-9.25t-9.25=0 equation:

t^2-9.25t-9.25=0

a = 1; b = -9.25; c = -9.25;
Δ = b2-4ac
Δ = -9.252-4·1·(-9.25)
Δ = 122.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9.25)-\sqrt{122.5625}}{2*1}=\frac{9.25-\sqrt{122.5625}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9.25)+\sqrt{122.5625}}{2*1}=\frac{9.25+\sqrt{122.5625}}{2}
$